Math, asked by sanilmalviya34, 6 months ago

Find the last digit of the number 1^3 + 2^3 +3^3 +.......+12/3?
Select one:
O a. 4
O b. 5
c. 3
d. 6​

Answers

Answered by Vasistha27
2

Answer:

3+9+27+81+243+729+2187+6561+19683+59049+177147+4=265723

c is the answer

Step-by-step explanation:

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Answered by swethassynergy
0

1^3 + 2^3 +3^3 +...+12^3 is a)4

Given:

1^3 + 2^3 +3^3 +...+12^3

To find:

The last digit of the number

Step-by-step explanation:

The given series is in the format of cubic numbers starting from 1³+2³+..+12³

1³⇒1×1×1 ⇒ 1

2³⇒2×2×2 ⇒ 8

3³⇒3×3×3 ⇒ 27

4³⇒4×4×4 ⇒ 64

5³⇒5×5×5 ⇒ 125

6³⇒6×6×6 ⇒ 216

7³⇒7×7×7 ⇒ 343

8³⇒8×8×8 ⇒ 512

9³⇒9×9×9 ⇒ 729

10³⇒10×10×10 ⇒ 1000

11³⇒11×11×11 ⇒ 1331

12³⇒12×12×12 ⇒ 1728

⇒(1+8+27+64+125+216+343+512+729+1000+1331+1728)

⇒6084

The last digit of the number is 4

The question is incorrect it should be as

Find the last digit of the number 1^3 + 2^3 +3^3 +...+12^3?

Select one:

a. 4

b. 5

c. 3

d. 6​

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