Find the last digit of the number 1^3 + 2^3 +3^3 +.......+12/3?
Select one:
O a. 4
O b. 5
c. 3
d. 6
Answers
Answer:
3+9+27+81+243+729+2187+6561+19683+59049+177147+4=265723
c is the answer
Step-by-step explanation:
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1^3 + 2^3 +3^3 +...+12^3 is a)4
Given:
1^3 + 2^3 +3^3 +...+12^3
To find:
The last digit of the number
Step-by-step explanation:
The given series is in the format of cubic numbers starting from 1³+2³+..+12³
1³⇒1×1×1 ⇒ 1
2³⇒2×2×2 ⇒ 8
3³⇒3×3×3 ⇒ 27
4³⇒4×4×4 ⇒ 64
5³⇒5×5×5 ⇒ 125
6³⇒6×6×6 ⇒ 216
7³⇒7×7×7 ⇒ 343
8³⇒8×8×8 ⇒ 512
9³⇒9×9×9 ⇒ 729
10³⇒10×10×10 ⇒ 1000
11³⇒11×11×11 ⇒ 1331
12³⇒12×12×12 ⇒ 1728
⇒(1+8+27+64+125+216+343+512+729+1000+1331+1728)
⇒6084
The last digit of the number is 4
The question is incorrect it should be as
Find the last digit of the number 1^3 + 2^3 +3^3 +...+12^3?
Select one:
a. 4
b. 5
c. 3
d. 6