Find the last digits of (456)^87*(307)^42
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Step-by-step explanation:
find the last digits of (456)^87*(307)^42. Ask for details; Follow; Report. by Khannaarsh8 1 week ago. Log in to add a brainlist.
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Answer:
4
Step-by-step explanation:
gives unit digit as 6 because 6 raised to any power will give 6 only.
whereas,
gives unit digit as 9 because the cyclicity of 7 is 4 and when 42 is divided by 4 gives remainder 2 and value at 2nd place in cycle of 7 is 9.
so 9*6 = 54
so unit digit will be 4
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