Question

Find the last number which when divided by 12 16 24 and 36 leaves a remainder 7 in each case

Answer 1

Answer:

For this particular sum we need to find the LCM of the given numbers.

The smallest number which when divided by 12 16 24 and 36 = LCM of 12 16 24 and 36

12 = 2×2×3

16 = 2×2×2×2

24 = 2×2×2×3

36 = 2×2×3×3

LCM = 144

The smallest number which divides 12 16 24 and 36 is 144. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151).

Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.

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