Question

Find the last number which when divided by 6,15and 18 leave a remainder 5 in each case​

Answer 1

Answer:

Least number which when divided by 6,15 and 18 leave the remainder 0

=LCM of 6,15,18

So, LCM leaves remainder 0

So, the Required number will be 5 more than LCM

∴ Required number=LCM+5

Factors of 6=2×3

Factors of 15=5×3

Factors of 18=2×3×3

∴ LCM=2×3×3×5=90

So, Required number=LCM+5=90+5=95

Answer 2

Answer:

the answer is 95

Step-by-step explanation:

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