Question

Find the last two digit of (4584756* 154-480)?
A] 78
B]56
C] 76
D] 24
​

Answer 1

Answer:

56

Step-by-step explanation:

Answer 2

Answer:

14

14

14

=196

2

14

14

=(200−4)

7.14

13

The last two digits of this number will be the same as the last two digits of

(−4)

7.14

13

=4

7.14

13

Now, notice that the last two digits of the even powers of 4 have the following 5 terms occurring periodically.

16,56,96,36,76

So, last two digits of 4

2

is 16

So, last two digits of 4

4

is 56

So, last two digits of 4

6

is 96

So, last two digits of 4

8

is 36

And, last two digits of 4

10

is 76

And this is repeated for 4

12

,4

14

……

Now, 4

7.14

13

has an even exponent to 4. Now we just need to find the last digit in this exponent and match it with one of the five cases listed above.

The last digit in 7.14

13

is the last digit in 7.(10+4)

13

Which is the same as last digit in 7×4

13

Which is the same as last digit in 28×4

12

Using the list above,

It is the same as last digit in 28×16 which is 8

Again using the list above, we have the final result as 36

Hence, answer is 36.