Math, asked by vanamsirishaprasad, 10 months ago

Find
the last
two digits of
3^1997​

Answers

Answered by NafisaMuskaan
2

Answer:

63

Step-by-step explanation:

3^1997

3*3^1996

3*(3^4)^499

3*(81)^499

Now we can do 81^499

Here unit place is 1 so 1 st place will be 1

After we will multiply 8*9=72 (10 th place of 81 * unit place of 499)

But we can write only unit place because we need only last 2 digits

So the two digit is 21

But here 3 was infront of this factor.

So we have to multiply by 3

So the last two digit will be 3*21=63

Answered by Anonymous
0

Step-by-step explanation:

the last

two digits of

3^1997

bbbb

bbbb

nnn

nnn

bnyyggj

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