Math, asked by SuitableBoy, 3 months ago

Find the last two digits of \bf{2^{1000}}


SuitableBoy: Hey
BhaumiP: Hi

Answers

Answered by Anonymous
21

\begin{gathered}\huge\star{\pink{\underline{\mathfrak{answer}}}}⋆ \\\end{gathered}

Step-by-step explanation:

To obtain the required last digit of 2^1000 :-

2 {}^{1000}  = (2 {}^{5} ) {}^{200}  = (32) {}^{200}

⇒2 {}^{1000}  = 2  {}^{200}

⇒2 {}^{1000}  = 2 {}^{200}  = (2 {}^{5}) {}^{8}

⇒2 {}^{1000}  = 2 {}^{8}

⇒2 {}^{1000}  = 256

⇒2 {}^{1000}  = 6

Required last digit is 6


SuitableBoy: Thank You ; but i asked for last two ( ✌) digits ..
Anonymous: The last two digit is 6
Anonymous: I gave the explanation as step-by-step , look again clearly.
Anonymous: :)
SuitableBoy: you mean : last two digits → 06 ??
Anonymous: Yeah....
SuitableBoy: ohh
Answered by hareem23
7

 \huge  \purple\star \pink  {answer} \huge \purple \star

Step-by-step explanation:

To obtain the required last digit of 2^1000 :-

2¹⁰⁰⁰= (2⁵)²⁰⁰ = (32)²⁰⁰

⇒2¹⁰⁰⁰ = 2²⁰⁰

⇒2¹⁰⁰⁰ = 2²⁰⁰ = (2⁵)⁸

⇒2¹⁰⁰⁰ = 2⁸

⇒2¹⁰⁰⁰ = 256

⇒2¹⁰⁰⁰ = 6

• Required last digit is 6


shonaansari7876: hi
Anonymous: You just copy pasted my answer -_-
SuitableBoy: lol XD
Anonymous: Like seriously @hareem23 , stop coping answers
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