find the lateral and total surface area of a triangular based pyramid with base 12 centimetre and slant height 20 centimetre
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base is equilateral triangle whose base =a= 12 cm
area of the base = √3/4 *a² =√3/4 * (12)²=36√3 cm²
1)lateral surface area =pl/2 where p = perimeter of the base =3*12=36cm
l= slant height = 20cm
lsa = (36*20)/2= 360cm²
2)total surface area = LSA +BASE AREA
=(360+36√3)cm²
area of the base = √3/4 *a² =√3/4 * (12)²=36√3 cm²
1)lateral surface area =pl/2 where p = perimeter of the base =3*12=36cm
l= slant height = 20cm
lsa = (36*20)/2= 360cm²
2)total surface area = LSA +BASE AREA
=(360+36√3)cm²
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