find the lateral surface area and the total surface area of the cuboids with the following dimensions
L=2dm, b=1dm, h=0.75dm
Answers
Answer:
lateral surface area=1/2(l+b)h
=1/2(2+1)0.75
=1/2*3*0.75
=1/2*2.25
=1.125dm^2
total surface area=2(lb+bh+hl)
=2(2*1+1*0.75+0.75*2)
=2(2+0.75+1.5)
=2*3.8
=7.6dm^2
Given:-
Length = 2 dm ( 2 dm → 0.2 m )
Breadth = 1 dm ( 1 dm → 0.1 m )
Height = 0.75 dm ( 0.75 dm → 0.075 m )
Solution:-
step-by-step explanation:
We know that
Volume of a cuboid = L × B × H
So,
= 0.2 × 0.1 × 0.075
= 0.0015cm³
Lateral surface area of cuboid = 2(L + B) × H
= 2(0.2 + 0.1) × 0.075
= 2 × 0.3 × 0.075
= 0.045 cm²
Total surface area of the cuboid = 2(Lb + Bh + Hl)
= 2(0.2 × 0.1 + 0.1 × 0.075 + 0.075 × 0.2)
= 2(0.02 + 0.0075 + 0.015)
= 2 × 0.0425
= 0.085 cm²
Required Answer
Lateral surface area of the cuboid is 0.045cm²
Total surface area of the cuboid is 0.085cm²