Math, asked by ritz33, 1 year ago

find the lateral surface area and the total surface area of a cube each of whose edge measures (a) 7 cm (b) 8 dm 5 cm

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Answers

Answered by Anonymous
209

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(a) 7 cm

Total surface area of a cube = 6{a}^{2}

》TSA = 6\times {7}^{2}

》TSA = 294 {cm}^{2}

Lateral surface area of cube = 4{a}^{2}

》LSA = 4\times {7}^{2}

》LSA = 196 {cm}^{2}

(b) 8 dm 5 cm

8 dm 5 cm = 85 cm

Total surface area of a cube = 6{a}^{2}

》TSA = 6\times {85}^{2}

》TSA = 43350 {cm}^{2}

Lateral surface area of cube = 4{a}^{2}

》LSA = 4\times {85}^{2}

》LSA = 28900 {cm}^{2}

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Answered by Ruwat
144
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<b><font face=Times New Roman size=4>
1) LSA of the cube

= 4a²

= (4 × 7²) cm²

= (4 × 49) cm²

= 196 cm²

TSA of the cube

= 6a²

= (6 × 7²) cm²

= (6 × 49) cm²

= 294 cm²

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2) 8dm 5 cm = 85 cm

LSA of the cube

= 4a²

= (4 × 85²) cm²

= (4 × 7225) cm²

= 28900 cm²

TSA of the cube

= 6a²

= (6 × 85²) cm²

= (6 × 7225) cm²

= 43350 cm²

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