Question

Find the lateral surface area of a cuboid whose length, breath and height are 1 m, 2 m and 1.5 m respectively​

Answer 1

Answer:

⇒ Length of a cuboid (l)=8cm

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm⇒ Total surface area of cuboid =2(lb+bh+hl)

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm⇒ Total surface area of cuboid =2(lb+bh+hl) =2(8×7+7×4+4×8)

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm⇒ Total surface area of cuboid =2(lb+bh+hl) =2(8×7+7×4+4×8) =2(56+28+32)

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm⇒ Total surface area of cuboid =2(lb+bh+hl) =2(8×7+7×4+4×8) =2(56+28+32) =2(116)

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm⇒ Total surface area of cuboid =2(lb+bh+hl) =2(8×7+7×4+4×8) =2(56+28+32) =2(116) =232cm

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm⇒ Total surface area of cuboid =2(lb+bh+hl) =2(8×7+7×4+4×8) =2(56+28+32) =2(116) =232cm 2

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm⇒ Total surface area of cuboid =2(lb+bh+hl) =2(8×7+7×4+4×8) =2(56+28+32) =2(116) =232cm 2

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm⇒ Total surface area of cuboid =2(lb+bh+hl) =2(8×7+7×4+4×8) =2(56+28+32) =2(116) =232cm 2 ∴ Total surface area of cuboid =232cm

⇒ Length of a cuboid (l)=8cm⇒ Breadth of a cuboid (b)=7cm⇒ Height of a cuboid (h)=4cm⇒ Total surface area of cuboid =2(lb+bh+hl) =2(8×7+7×4+4×8) =2(56+28+32) =2(116) =232cm 2 ∴ Total surface area of cuboid =232cm 2

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

6 m was correct ans of this que