Find the lateral surface area of a cuboidal box whose perimeter of the base is 56cm and height is one fourth the sum of it's length and breadth
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Dear mates here is your solution:-
Let the length, breadth and height of the cuboidal box be l, b and h respectively. Then
Given perimeter of base
=>2*(l+b)=56cm
=> (l+b) =28cm
Now it is given that
H=(l+b) /4
=>H=28/4
=>H=7 cm
Now we know what
'' Lateral surface area of a cuboid = Sum of the areas of its 4 lateral rectangular faces''
=>L. S. A= 2h(b+l) cm2
=2*7(28)
=392 cm2
Hence, the lateral surface area of the given cuboidal box is 392 cm2.
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aarush29:
hi
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