Question

find the lateral surface area of a right circular cyclinder if it has base diameter 6 and its hight is 12

Answer 1

C.S.A of cylinder=2πrh
=2*3.14*3*12
=226.08

Answer 2

$\textbf{ Heya Mate }$

$\textbf{Given}$

Base diameter = 6

$\textbf {Therefore}$, base radius = 3
Height = 12

$\textbf{Now}$

We know,

Lateral surface area of a right circular cylinder is 2πrh

$\textbf{So Now}$

The lateral surface area of right circular cylinder = 2πrh

= 2× $\frac{22}{7}$ × 3 × 12

= $\frac{1584}{7}$

= 226.2857 (approx)

$\textbf{Hope this helps you }$
$\textbf{Be Brainly}$