Question

find the lateral surface area of a right circular cylinder,if its base f=has radius 3cm and its height is 5cm​

Answer 1

★ Given:

Radius of right circular cylinder = 3 cm

Height = 5 cm

★ To Find:

The LSA of the cylinder.

★ Solution:

Formula to find LSA = 2πrh

Taking π as 22/7.

$\sf{2\times\dfrac{22}{7}\times3\times5}$

= 94.25 cm²

Hence the LSA of the right circular cylinder is 94.25 cm².

Knowledge Bytes:

→ Right Circular Cylinder

A cylinder with identical circular bases and an axis that joins the bases perpendicularly is known as a right circular cylinder.

→ Formulae Related to Cylinder

✳ LSA = 2πrh

✳ TSA = 2πr (r + h)

✳ Volume = πr²h

Answer 2

$\sf{Answer}$

Step by step explanation:-

Given :-

Right circular cylinder has

• Radius = 3cm
• Height = 5cm

To find :-

LSA of cylinder

Formula implemented :- 2πrh

Solution:-

LSA of cylinder = 2πrh

π = $\sf\dfrac{22}{7}$

LSA of cylinder = 2πrh

LSA = 2 × $\sf\dfrac{22}{7}$ × 3 cm× 5 cm

LSA = $\sf\dfrac{2×22×15cm²}{7}$

LSA = $\sf\dfrac{660cm²}{7}$

LSA = 94.28 cm²

So, LSA Of cylinder is 94.28cm²

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