Question

find the lateral surface area of two pillars if height of the pillar is 21 m and radius of the base is 2.1 m
​

Answer 1

Step-by-step explanation:

Answer

The height of pillar is 500cm

The radius of pillar is 21cm

The surface area is 2πrh

2×

7

22

×21×500

6×22×500=66000

Surface area of 4 pillars is 4×66000=264000cm

2

Answer 2

⛦ Given :

• height of the pillar = 21m
• Radius of the base = 2.1m

⛦To Find:-

• The lateral surface area of two pillars

⛦solution:-

We know that:-

Lateral surface area of two pillars

= 2 × Curved surface area

According the question,

∴ 2 × 2πrh

$= 2 \times 2 \times \dfrac{22}{7} \times 2.1 \times 21$

$= 2 \times 2 \times 22 \times 2.1\times3$

$= 4 \times 22 \times 2.1 \times 3$

$= 88 \times 6.3$

$\bf{ = 554.4 {m}^{2}}$

$\Large{\underbrace{\sf{\purple{Required\:Answer:}}}}$

$\large\longrightarrow{\boxed{\sf{\red{ 554.4m²}}}}$

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$\Large{\underbrace{\sf{\orange{Explore\:More!}}}}$

•Volume of Cylinder = πr²h cubic units

•Total surface area of cylinder = 2πr( h + r ) sq.units

•Curved surface area of cylinder = 2πrh sq.units

•Diagonal of a cube = a√3 units

•Lateral surface area of a cube for = 4a² sq.unit

•Volume of a cube = a³ cubic units.

•Diagonal of a cuboid = $\sqrt{L² + b² + h²}$

•Volume of a cuboid = ( L + b + h ) cubic units.

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