Question

Find the lateral surface ate of two pillars if height of the pillar is 7m and radius of the base is 1.4m.
​

Answer 1

Given :

• Height of Pillar is 7 m .
• Radius of Pillar is 1.4 m.

To Find :

• Lateral Surface Area of Two Pillars .

Solution :

Firstly we will find Lateral Surface Area of 1 pillar :

$\longmapsto\tt{Radius(r)=1.4\:m}$

$\longmapsto\tt{Height(h)=7\:m}$

Using Formula :

$\longmapsto\tt\boxed{L.S.A\:of\:Cylinder=2\pi{rh}}$

Putting Values :

$\longmapsto\tt{2\times\dfrac{22}{{\not{7}}}\times{1.4}\times{{\not{7}}}}$

$\longmapsto\tt{2\times{22}\times{1.4}}$

$\longmapsto\tt{44\times{1.4}}$

$\longmapsto\tt\bf{61.6\:{m}^{2}}$

Now ,

Lateral Surface Area of 2 pillars :

$\longmapsto\tt{61.2\times{2}}$

$\longmapsto\tt\bf{123.2\:{m}^{2}}$

So , The Lateral Surface Area of Two Pillars is 123.2 m² .

_______________________

• L.S.A / C.S.A of Cylinder = 2πrh
• T.S.A of Cylinder = 2πr(r+h)
• Volume of Cylinder = πr²h

Here :

• π = 22/7 or 3.14
• r = Radius
• h = Height

_______________________

Answer 2

Answer:

123.2 m²

Step-by-step explanation:

$\text{\large\underline{\green{Given:}}}$

• Height of pillar (h) = 7 m
• Radius of bas (r) = 1.4 m

$\text{\large\underline{\purple{To\:find:}}}$

• The LSA of two pillars = ?

$\text{\large\underline{\pink{Solution:}}}$

We know that the height of pillar is 7 m and the radius is 1.4 m and we have to calculate the lateral surface area of two pillars.

$\sf\blue{\implies \: LSA \: of pillar \: or \:cylinder \: = 2\pi rh}$

Let's find the LSA of 1 pillar first !

$\implies$ LSA = $\dfrac{2\:×22\:×7\:×\:1.4}{7}$

$\implies$ LSA = $\dfrac{44\:×1.4}{7}$

$\implies$ LSA = $\dfrac{308}{5}$

$\implies$ LSA = 61.6 m²

Hence, the LSA for 1 pillar is 61.6 m².

LSA for 2 pillars:

$\implies$ 61.6 × 2

$\implies$ 123.2 m²

${\large{\boxed{\sf{\therefore \:LSA\:of\:two\:pillars\:is\:123.2\:m²}}}}$

Hope it helped you dear...