Question

Find the lateral surface ate of two pillars if height of the pillar is 7m and radius of the base is 1.4m.​

Answer 1

Answer:

• Lateral surface area of two pillars is 122.2 m².

Step-by-step explanation:

Given that,

Height of pillar is 7 cm.

Radius of the base is 1.4 m

We know,

Shape of pillar is cylinder.

• First we will find lateral surface area of one pillar.

Lateral surface area of cylinder = 2πrh

• Here, r and h are radius and height of cylinder.

Putting, r and h in formula

$\longrightarrow$ 2 × 22/7 × 1.4 × 7

$\longrightarrow$ 44/7 × 9.4

$\longrightarrow$ 431.2/7

$\longrightarrow$ 61.6

Lateral surface area of one pillar is 61.6 m².

Lateral surface area of two pillars = 2 × Lateral surface area of one pillar.

$\longrightarrow$ 2 × 61.6

$\longrightarrow$ 122.2

Therefore,

Lateral surface area of two pillars is 122.2 m².

Answer 2

Answer:

$\huge \tt \: given$

$\sf \: height \: of \: pillar \: = 7 m$

$\sf \: base \: of \: pillar = 1.4 \: m$

$\huge \tt \: to \: find$

Lateral surface of 2 such pillar

$\huge \tt \: solution$

$\bf \: \: lateral \: surface\: area = 2\pi \: rh$

$\tt \: 2( \frac{22}{7} )(1.4)(7)$

$\tt \: 2 \times 22 \times 1.4$

$44 \times 1.4$

$\huge \bf \: 61.6$

Therefore one surface lateral area = 61.6 m

$\sf \: lateral \: surface \: of \: 2 \: pillar \: = 61.6 \times 2$

$\sf \: 122.2$

Therefore surface lateral area of 2 pillar is 122.2 m

Here

R = Radius (We considered this as base)

H = Height

π = 22/7