Question

Find the lateral surface ate of two pillars if height of the pillar is 7m and radius of the base is 1.4m.​

Answer 1

Answer:

Lateral surface area of two pillars is 122.2 m².

Step-by-step explanation:

Given that,

Height of pillar is 7 cm.

Radius of the base is 1.4 m

We know,

Shape of pillar is cylinder.

First we will find lateral surface area of one pillar.

Lateral surface area of cylinder = 2πrh

Here, r and h are radius and height of cylinder.

Putting, r and h in formula

$\longrightarrow 2 × 22/7 × 1.4 × 7$

$\longrightarrow 44/7 × 9.4$

$\longrightarrow 431.2/7$

$\longrightarrow 61.6$

Lateral surface area of one pillar is 61.6 m².

Lateral surface area of two pillars = 2 × Lateral surface area of one pillar.

$\longrightarrow 2 × 61.6$

$\longrightarrow 122.2$

Therefore,

Lateral surface area of two pillars is 122.2 m².

Answer 2

123.2$m^{2}$

Pillar is in the shape of cylinder

Given the height = 7m

radius of base = 1.4m

Lateral surface area of pillar = 2$\pi$rh

substituting the values

L.S.A = 2($\frac{22}{7}$)(1.4)(7)  ( $\pi$= $\frac{22}{7}$)

=2(22)(1.4)

=61.6 $m^{2}$

Since we have to find the lateral surface area of two pillars

L.S.A = 2×61.6 $m^{2}$

=123.2 $m^{2}$