Question

find the LCF and HCF of 270, 315and 405 using fundamental theorem of Arithmetic​

Answer 1

Answer:

Step-by-step explanation:

Prime factorization of 270 =2×3×3×3×5

Prime factorization of 315=3×3×5×7

Prime factorization of 405=3×3×3×3×5

So,HCF(270,315,405)=3×3×5

=45(ans).

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Answer 2

$HCF(270,315,405)=45$

$LCM(270,315,405)=5670$

Step-by-step explanation:

To find : The LCF and HCF of 270, 315 and 405 using fundamental theorem of Arithmetic​ ?

Solution :

Prime factor of the numbers 270, 315 and 405

$270 =2\times 3\times 3\times 3\times 5$

$315 =3\times 3\times 5\times 7$

$405=3\times 3\times 3\times 3\times 5$

The HCF is the highest common factor.

$HCF(270,315,405)=3\times 3\times 5$

$HCF(270,315,405)=45$

The LCM is the least common multiple.

$LCM(270,315,405)=2\times 3\times 3\times 3\times 3\times 5\times 7$

$LCM(270,315,405)=5670$

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