find the LCM & HCF of x² + 2x - 3
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Step-by-step explanation:
x
4
+2x
3
+3x
2
+2x+1=(x
2
+x+1)(x
2
+x+1)
x
3
−1=(x−1)(x
2
+x+1)
x
3
+x
2
+x=x(x
2
+x+1)
x
2
y+yx+y=y(x
2
+x+1)
L.C.M. =(x
2
+x+1)
2
(x−1)xy
and, H.C.F. =x
2
+x+1.
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