Question

find the LCM and HCF of 26 and 96 and verify that LCM multiply HCF = product of two numbers​

Answer 1

Answer:

Resolving the given Numbers

into prime factors , we get

404 = 2 × 2 × 101 = 2² × 101

96 = 2×2×2×2×2×3 = 2^5×3

HCF(404,96) = 2² = 4

[ Product of the smallest power

of each common prime factors

of the numbers ]

LCM( 404,96) = 2^5 × 101 × 3

= 9696

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We know that ,

If h, l are HCF and LCM of

two numbers a and b then

l × h = a × b

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Verification :

l = 9696 ,

h = 4 ,

a = 404 ,

b = 96

l × h = 9696 × 4 = 38784 --(1)

a × b = 404 × 96 = 38784---(2)

Therefore ,

From (1) and (2) , we conclude

that

l × h = a × b

•••••

Answer 2

Answer:

1. step = product of two number is = Hcf × Lcm

2. step =product of two number is = 26×96

3. step =product is two number is = 2496 answer