Question

Find the LCM and HCF of 510 and 92 and verify that LCM×HCM=Product of the two numbers.​

Answer 1

Step-by-step explanation:

HCF of 510 and 92.

510 = 92 x 5 + 50 92

= 50 x 1 + 42 50

= 42 x 1 + 8 42

= 8 x 5 + 2 8

= 2 x 4 + 0

Therefore, HCF of 510 and 92

= 2

Product of two numbers = Product of their LCM and HCF

510 x 92 = 2 x LCM

LCM = (510 x 92) / 2

= 23460

∴ LCM of 510 and 92 = 23460.

Answer 2

Prime factorisation of 510=2×3×5×17

Prime factorisation of 92=2×2×23

Hence,LCM of 510,92=2×3×5×17×2×23=23460

And HCF of 510,92=2

Now,LCM×HCF=23460×2=46920

• Also,510×92=46920

i.e.,HCF×LCM=Product of the 2 numbers.