Question

find the lcm and hcf of following pair of integers and varifie that lcm× hcf = product of two number 96×404

Answer 1

using prime factorisation

HCF of 96 = 2 × 2× 2 ×2 ×2 × 3

HCF of 404 = 2 × 2 ×101

HCF of ( 96,404) = 2 ×2

=4

using ecluid THEOREM

LCM ( 96 , 404 ) = Product of 96 and 404 /HCF ( 96 , 404)

96 × 404 /4

= 96 × 101

= 9696

product of number = 96 ×404

= 38784

HCF (96 ,404 ) × LCM (96,404)

= 4×9696

=38784

HENCE VERIFIED....