Question

Find the LCM and HCF of following pairs of integers and verify that HCF×LCM = product of the Integers. 26 and 91​

Answer 1

Answer:

If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs. So the product of L.C.M and H.C.F is $\left( {182 \times 13} \right) = 2366$. And the product of two numbers is $\left( {26 \times 91} \right) = 2366$.