Question

find the Lcm and hcf of i) 30,72,432 ii) 21,28,36,45 ​

Answer 1

Answer:

Step-by-step explanation:

Please see the attached explanation

Answer 2

HCF of 30, 72 and 432

30 = 2 × 3 × 5

72 = 2 × 2 × 2 × 3 × 3

432 = 2 × 2 × 2 × 2 × 3 × 3 × 3

There HCF of 30, 72 and 432 is 2 × 3 = 6

LCM of 30, 72 and 432 is 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5 = 2160

HCF is 6 and LCM is 2160

21 = 3 × 7

28 = 2 × 2 × 7

36 = 2 × 2 × 3 × 3

45 = 3 × 3 × 5

Now hcf is the common one

Therefore hcf = 1 (as there are no common factor )

lcm = 2 × 2 × 3 × 3 × 5 × 7 = 1260

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