Math, asked by klchowdhary774, 7 months ago

find the lcm and hcf of m3+64 and m2-16​

Answers

Answered by welldonesharmaji890
0

Step-by-step explanation:

Here,

1st exp. = m^3 + 64

= (m)^3 + (4)^3

= (m+4)(m^2 - 4m + 16)

2nd exp. = m^2 - 16

= (m)^2 - (4)^2

= (m+4)(m-4)

Therefore, HCF = common factor above both exp.

= m + 4

And, LCM = common × remaining factors

= (m+4)(m-4)(m^2 - 4m + 16)

= (m-4)(m^3 + 64)

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