find the lcm and hcf of the following inegers by applying the prime factorisation method (i)12, 15and 21 (ii)17, 23and 29 (iii) 8, 9and 25
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Answer:
Step-by-step explanation:
1 hcf=3 lcm 420
2hcf=1 and lcm 11339
3 hcf=1 lcm =1800
Answered by
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Answer:
1. LCM OF 12, 15 & 21 = 420
2. LCM OF 17, 23 & 29 = 11339
3. LCM OF 8, 9 & 25 = 1800
Step-by-step explanation:
1. LCM OF 12 = 2×2×3
LCM OF 15 = 3×5
LCM OF 21 = 3× 7
= LCM OF 12, 15 & 21 = 2²×3×5×7 = 420
2. LCM OF 17 = 17×1
LCM OF 23 = 23×1
LCM OF 29 = 29×1
LCM OF 17,23 & 29 = 17×23×29= 11339
3. LCM OF 8 = 2×2×2
LCM OF 9 = 3×3
LCM OF 25 = 5×5
LCM OF 8, 9 & 25 = 8×9×25= 1800
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