find the LCM and HCF of the following integers by applying the prime factorization 448 1008 and 168
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Answered by
2
heya.....
here is your answer
448→2*2*2*2*2*2*7
1008→2*2*2*2*3*3**7
168→2*2*2*3*7
HCF= 2*2*2*7 = 56
LCM =2*2*2*7*2*2*2*3*3*3=12096
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hope it helps!!
here is your answer
448→2*2*2*2*2*2*7
1008→2*2*2*2*3*3**7
168→2*2*2*3*7
HCF= 2*2*2*7 = 56
LCM =2*2*2*7*2*2*2*3*3*3=12096
◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎◎
hope it helps!!
Answered by
2
Hiii friend,
Prime factorisation of 448 = 2 × 2 × 2 × 2 × 2 × 2 × 7
Prime factorisation of 1008 = 2 × 2 × 2 × 2 × 3 × 3 × 7
Prime factorisation of 168 = 2 × 2 × 2 × 3 × 7
Therefore,
HCF of 448 , 1008 and 168 = 2 × 2 × 2 × 7 = 56
LCM of 448 , 1008 and 168 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 7 = 12096
HOPE IT HELPS!!!!!
Prime factorisation of 448 = 2 × 2 × 2 × 2 × 2 × 2 × 7
Prime factorisation of 1008 = 2 × 2 × 2 × 2 × 3 × 3 × 7
Prime factorisation of 168 = 2 × 2 × 2 × 3 × 7
Therefore,
HCF of 448 , 1008 and 168 = 2 × 2 × 2 × 7 = 56
LCM of 448 , 1008 and 168 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 7 = 12096
HOPE IT HELPS!!!!!
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