find the LCM and HCF of the following integers by the prime factorization method 12,15 and 21
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0
Answer:
Solution:
Factor of 12=2×2×3
Factor of 15=3×5
Factor of 21=3×7
HCF (12,15,21)=3
LCM (12,15,21)=2×2×3×5×7=420
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Step-by-step explain
LCM = 420 & HCF = 3
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