Question

find the Lcm and HCF of the following pairs
If integers and verify that Lom Hefa
product of the two number.
12, 15 and 2 (i) 17,23 and 29 (1) 8, a and 28​

Answer 1

Answer:

let me solve in copy first then I'll write it here

Step-by-step explanation:

1. hcf of 12=2×2×3

15=3×5×1

2=2×1

lcm=2²×3×5=60

1. hcf of 17,23 and 29

17=17×1

23=3×7×1

29=29×1

hcf=1

lcm=17×23×29= 11339

hcf=maybe Ur question lill wrong i don't know check it 8 a??? give stars plz

Answer 2

:

Mark Me As Brainliest And Thank Me If The Answer Is Useful.

-- :

Using prime factorisation method:

(i) 12, 15 and 21

Factor of 12=2×2×3

Factor of 15=3×5

Factor of 21=3×7

HCF (12,15,21)=3

LCM (12,15,21)=2×2×3×5×7=420

(ii) 17, 23 and 29

Factor of 17=1×17

Factor of 23=1×23

Factor of 29=1×29

HCF (17,23,29)=1

LCM (17,23,29)=1×17×23×29=11,339

(iii) 8, 9 and 25

Factor of 8=2×2×2×1

Factor of 9=3×3×1

Factor of 25=5×5×1

HCF (8,9,25)=1

LCM (8,9,25)=2×2×2×3×3×5×5=1,800