Find the LCM and HCF of the following pairs of integers and verify that LCM multiply HCF= product of the two numbers is 336 and 54.
Answers
Step-by-step explanation:
Secondary School Math 15+8 pts
Find the LCM and HCF of the following pairs of integers and verify that LCM x HCF = product of the integers:
(i)26 and 91
(ii)510 and 92
(iii)336 and 54
by BrainlyHelper 17.11.2018
Report
Answers
nikitasingh79
Nikitasingh79★ Brainly Teacher ★
SOLUTION :
(i) Given :First number : 26
Second number : 91
The prime factors of 26 and 91 are :
26 = 2 x 13
91= 7 x 13
L.C.M (26,91) = 2 x 7 x 13
L.C.M of (26, 91) =182
[LCM of two or more numbers = product of the greatest power of each prime factor involved in the numbers, with highest power.]
H.C.F of (26, 91) = 13
[HCF(Highest Common Factor) of two or more numbers= Product of the smallest Power of each common prime factor involved in the numbers.]
We know that, L.C.M x H.C.F = First number x Second number
182 x 13 = 26 x 91
2366 = 2366
Hence verified
by this process you can simplify...
Answer:
HOPE THIS BRING A SMILE IN YOUR FACE
Step-by-step explanation:
