Question

find the lcm and hcf of the following pairs of integers and verify lcm and hcf = product of two numbers.

(i) 26 and 91
(ii)510 and 92
(iii)336 and 54​

Answer 1

$(i)LCM\ of\ 26\ and\ 91=182\\HCF\ of\ 26\ and\ 91=13\\Now,\\LCM×HCF=182×13=2366\\and,\\Product(26,91)=26×91=2366.\\Therfore,\\LCM×HCF=Product\\Hence\ verified.\\\\(ii)LCM(510,92)=23460\\HCF(510,92)=2\\Now,\\LCM×HCF=23460×2=46920\\and,\\Product(510,92)=46920\\Therefore,\\LCM×HCF=Product\\Hence\ Verified.\\\\(iii)LCM(336,54)=3024\\HCF(336,54)=6\\Now,\\LCM×HCF=3024×6=18144\\and,\\Product(336,54)=18144\\Therefore,\\LCM×HCF=Product\\Hence\ verified.$

Answer 2

Answer:

1. By prime factorisation

26=2*13

91=7*13

Therefore HCF is 13

and LCM is 2*7*13=182

Now,

Lcm*Hcf=Product of the number

13*182=26*91

2366=2366

Hence,LHS=RHS

2.By prime factorisation,

510=2*3*5*17

92=2*2*23

Therefore, HCF is 2

and LCM is 2*2*3*5*17*23=23460

Now,

Lcm*Hcf=product of the number

2*23460=510*92

46920=46920

Hence, LHS=RHS

3.By prime factorisation,

336=2*2*2*2*3*7

54=2*3*3*3

Therefore,HCF is 2*3=6

and LCM is 2*2*2*2*3*3*3*7=3024

Now,

Lcm*hcf=product of the number

3024*6=336*54

18144=18144

Hence,LHS=RHS

Hence, verified .

__________________________

Hope this helps u

plz don't forget to mark it as brainliest

Regards

NaVila11

Thank you

#followpls#