find the lcm and hcf of the following pairs of integers and verify the lcm and hcf = product of the numbers 510 and 92
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Hey mate !!
Here's your answer !!
HCF ( 510,92 ) can be found using Euclid's division algorithm.
510 = 92 × 5 + 50
92 = 50 × 1 + 42
50 = 42 × 1 + 8
42 = 8 × 5 + 2
8 = 2 × 4 +0
Hence 2 is the HCF of 510 and 92.
LCM ( 510,92 ) = Product of high powers between the two numbers.
510 = 2 × 3 × 5 × 17
92 = 2 × 2 × 23 = 2² × 23
So LCM = 2² × 3 × 5 × 17 × 23 = 23460
Verification:
HCF × LCM = Product of 2 numbers
= 2 × 23460 = 510 × 92
= 46920 = 46920
=> LHS = RHS
Hence verified.
Hope this helps !!
Cheers !!
____________________________________________________________
# Kalpesh :)
Hey mate !!
Here's your answer !!
HCF ( 510,92 ) can be found using Euclid's division algorithm.
510 = 92 × 5 + 50
92 = 50 × 1 + 42
50 = 42 × 1 + 8
42 = 8 × 5 + 2
8 = 2 × 4 +0
Hence 2 is the HCF of 510 and 92.
LCM ( 510,92 ) = Product of high powers between the two numbers.
510 = 2 × 3 × 5 × 17
92 = 2 × 2 × 23 = 2² × 23
So LCM = 2² × 3 × 5 × 17 × 23 = 23460
Verification:
HCF × LCM = Product of 2 numbers
= 2 × 23460 = 510 × 92
= 46920 = 46920
=> LHS = RHS
Hence verified.
Hope this helps !!
Cheers !!
____________________________________________________________
# Kalpesh :)
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