Question

Find the LCM and HCF of the following pairs of integers and verify that LCM×HCF= product of the two numbers of 510 and 92

Answer 1

let,
a = 510
b = 92

LCM = 23460

HCF = 2

LCM × HCF = a × b

23460 × 2. = 510 × 92

46920. = 46920



LHS. = RHS .


hope it might be helpful !!

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

$\begin{array}{r | 1} 2 & 510 \\ \cline{2-2} 2 & 255 \\ \cline{2-2} 5 & 85 \\ \cline{2-2} & 17 \end{array}$

$\begin{array}{r | 1} 2 & 92 \\ \cline{2-2} 2 & 46 \\ \cline{2-2} & 5 \end{array}$

510 = 2 × 3 × 5 × 17

92 = 2² × 23

★HCF(510,92) = 2

★LCM (510,92)

= 2² × 3 × 5 × 23 × 17

= 23460

★Verification :-

HCF × LCM = 2 × 23460 = 46920

510 × 92 = 46920

★Hence Proved

LCM × HCF = Product of two numbers.