Question

Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF =

product of the two numbers.

(i) 26 and 91​

Answer 1

Given integers are: 26 and 91

First, find the prime factors of 26 and 91.

26 = 2 × 13

91 = 7 × 13

∴ L.C.M (26, 91) = 2 × 7 × 13 = 182

And,

H.C.F (26, 91) = 13

Verification:

L.C.M × H.C.F = 182 x 13= 2366

And, product of the integers = 26 x 91 = 2366

∴ L.C.M × H.C.F = product of the integers

Hence verified.