find the lcm and hcf of the integers 26 and 91 and verify that lcm × hcf = 26 × 91
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Answered by
16
Answer:
Step-by-step explanation:
26=2*13
91=7*13
so HCF=13
and LCM=2*7*13=182
hcf*lcm=13*182=13*2*91
=26*91
hcf*lcm=26 * 91
Answered by
8
By prime factorisation,
26 = 2¹ × 13¹
91 = 7¹ × 13¹
Now, HCF(26, 91) = 13
Also, LCM(26, 91) = 2¹ × 13¹ × 7¹.
Now we have to verify that,
LCM(26, 91) × HCF(26, 91) = 26 × 91
{LCM(a, b) · HCF(a, b) = a · b}
LHS:
(2 × 13 × 7)(13)
= 2 × 13 × 7 × 13
= 26 × 91
RHS:
= 26 × 91 = LHS.
Hence, proved.
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