Math, asked by shivanshu0005, 9 months ago

FIND THE LCM AND HCF OF THE INTEGERS AND VEIFY THAT LCM*HCF=PRODUCT OF THE FOLLOWING OF THE TWO NO.
(i) 26 AND 91

Answers

Answered by rajnitiwari192003
2

Answer:

26 & 91

26=2×13

91=7×13

HCF=13

LCM=13*2*7

LCM=182

a×b= HCF × LCM

26×91= 13×182

2366=2366

Answered by pranav9731646051
1

Answer:

26=2×13

91=7×13

HCF=13

LCM=13×2×7

=182

now,

HCF×LCM=PRODUCT ID GIVEN TWO NUMBERS

13×182=26×91

2366=2366

therefore,hcf×lcm=product of given two numbers.

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