Question

Find the LCM of 2 + 2cd + 2, 2 – 2, and c – d.

Answer 1

let use the bracket,
= (2+2cd+2)(2 -2)(c-d)

first we do the 1st and second,

=2(2+2cd+2)-2(2+2cd+2) (c-d)

=4+4cd+4-4-5cd-4 (c-d)

=4+4-4-4+4cd-5cd "

=4+4-4-4+1cd "
=4+4+8+1cd "
= 16+cd or cd+16 "

now we do the 3rd ,
= (cd + 16)(c-d)

=c(cd+16)-d(cd+16)

=c square d +16c-cd square -16d

= c^d+16c-cd^-16d
Thus,answer= c^d-cd^+16c-16d