Question

find the LCM of 2(x+1) , 3 (x+1)​

Answer 1

Correct option is

D

(x−1)(x−2)(x

2

−3x+3)

We know that the least common multiple (LCM) is the smallest number or expression that is a common multiple of two or more numbers or algebraic terms.

We first factorize the given polynomials as shown below:

(x−1)(x−2)(x

2

−3x+3)=(x−1)(x−2)(x

2

−3x+3)

(x−1)=(x−1)

(x

3

−4x

2

+6x−3)=(x−1)(x

2

−3x+3)

Now multiply all the factors, using each common factor only once, therefore, the LCM is:

=(x−1)(x−2)(x

2

−3x+3)