Question

Find the LCM of (2x^2-8),(3x^2-9x+6),(6x^2+18x+12)

Answer 1

Step-by-step explanation:

2x² - 8. = 2(x+2) ( x-2)

3x²-9x+6= 3( x²-3x+2). = 3( x-1) ( x-2)

6x²+18x+12= 6( x²+3x+2). = 6(x+1) ( x+2)

LCM= 6( x-1)(x+1)(x+2)(x-2). = 6( x²-1)(x²-4)

= 6( x⁴-5x²+4)

= 6x⁴ -30x²+24 ans

Answer 2

Answer:

The correct answer to this question is $6x^{4} - 30x^{2} + 24$

Step-by-step explanation:

Given - $(2x^2-8),(3x^2-9x+6),(6x^2+18x+12)$

To Find - Find the LCM

LCM is -

$2x^{2} - 8. \\= 2(x+2) ( x-2)$

$3x^{2} - 9x+6= 3( x^{2} - 3x+2)\\ = 3( x-1) ( x-2)$

$6x^{2} + 18x+12 \\6( x^{2} + 3x+2)\\ = 6(x + 1) ( x+2)$

$6( x-1)(x+1)(x+2)(x-2)\\ = 6( x^{2} - 1)( x^{2} - 4)$

$6( x^{4} -5x^{2} + 4)\\= 6x^{4} - 30x^{2} + 24$

The acronym LCM means least common multiple. When you multiply a number by a whole number, you obtain a multiple (greater than 0). A factor is a number that is produced when a whole number is multiplied by another number.

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