find the LCM of 6(x^2-3x+2) and 18 (x^2-4x+3)
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Answer:
Required L.C.M,
=6×3(x−1)(x−2)(x−3)
=18(x−1)(x−2)(x−3)
Step-by-step explanation:
6(x
2
−3x+2) and 18(x
2
−4x+3)
Expression 6(x
2
−3x+2)
=2×(x
2
−2x−x+2)
=2×3[x(x−2)−1(x−2)]
=2×3×(x−1)(x−2)
and 18(x
2
−4x+3)
=2×3×3(x
2
−4x+3)
=2×3×3[x(x−3)−1(x−3)]
=2×3×3(x−1)(x−3)
Required L.C.M,
=6×3(x−1)(x−2)(x−3)
=18(x−1)(x−2)(x−3)
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