find the lcm of 96 and 404 by the prime factorisation method
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hy there here is the best answer
HCF of 96 and 404 by prime factorisation method:-
Since, 96 = 2 × 2 × 2 × 2 × 2 × 3
and, 404 = 2 × 2 × 101
So, HCF of 96 and 404 = Product of common prime factors
= 2 × 2 = 4
LCM = 2 × 2 × 2 × 2 × 2 × 101 × 3
= 9696
Hope this help u and good luck:)
HCF of 96 and 404 by prime factorisation method:-
Since, 96 = 2 × 2 × 2 × 2 × 2 × 3
and, 404 = 2 × 2 × 101
So, HCF of 96 and 404 = Product of common prime factors
= 2 × 2 = 4
LCM = 2 × 2 × 2 × 2 × 2 × 101 × 3
= 9696
Hope this help u and good luck:)
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AnjulAnkita111:
but I want LCM
Answered by
1
Step-by-step explanation:
Let a=404 and b=96
Expressing the number as a product of prime number
404=2×2×101
96=2×2×2×2×2×3
∴ LCM of 404 and 96 is 2×2×2×2×2×101×3=9696
∴ HCF of 404 and 96 is 2×2=4
Now HCF×LCM=4×9696=38784
Product of two given numbers 404×96=38784
Hence HCM×LCM= product of two given numbers.
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