find the LCM of smallest 5 digit number
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Answer:
To find Smallest 5-Digit number divisible by 72 and 78. LCM = 2 x 2 x 2 x 3 x 3 x 3 = 216. Now, To find Required 5-digit number we divide 10000 by 216. Therefore, Required 5-digit number is 10152
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Step-by-step explanation:
the smallest 5 digit no= 10000
lcm=
10000/2=_____ans
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