Question

Find the LCM of the following monomials: 14xy^2, 28z^3y^2, 56xy^2z
Plz answer quickly

Answer 1

Answer:

56xy²z³

Step-by-step explanation:

Let a=14xy²

b=28z³y²

c=56xy²z

first find LCM of 14.28,56

factors of 14,28,56 are

24=2*7

28=2*2*7

56=2*2*2*7

So LCM=2*2*2*7=56

Now in a,b and c we see

the height power of

x is 1

y is 2

z is 3

So in LCM we should multiply the  highest power of x,y and z

hence LCM of

a,b,c = 56*x*y²*z³=

=56xy²z³