Math, asked by iqbal123ars, 6 hours ago

Find the LCM of the polynomials x² - 9 and x² - 6x + 9 ​

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Answered by kingoffather
0

Answer:

Expression x2 + 6x + 9 = (x)2 + 2 × x × 3 + (3)2 x3 + 4x2 + 4x + 3 = (x + 3)(x2 + x + 1) …(iii) common factor of eqn. (i), (ii) and (iii) = (x + 3) Thus, required H.C.F. = (x + 3) in eqns. (i), (ii) (iii) = (x + 3)2 (x – 4) (x2 + x + 1) = (x2 + 6x + 9) (x3 – x2 + x – 4x2 – 4x – 4) Hence, required L.C.M = (x2 + 6x + 9) (x3 – 5x2 – 3x – 4)Read more on Sarthaks.com - https://www.sarthaks.com/750958/find-l-c-m-and-h-c-f-of-the-followingexpression-x-2-6x-9-x-2-x-12-x-3-4x-2-4x-3

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