Question

Find the LCM of two numbers if their is140 and the HCF is 2

Answer 1

Answer:

Appropriate Question :-

• Find the LCM of two numbers if there product is 140 and the HCF is 2.

Given :-

• The product of two numbers is 140 and the HCF is 2.

To Find :-

• What is the LCM of two numbers.

Solution :-

Let,

$\mapsto$ LCM of two numbers = x

Given :

$\bigstar$ Product of two numbers = 140

$\bigstar$ HCF = 2

As we know that :

$\longmapsto \sf\boxed{\bold{\pink{HCF \times LCM =\: Product\: of\: two\: numbers}}}$

According to the question by using the formula we get,

$\implies \sf 2 \times x =\: 140$

$\implies \sf 2x =\: 140$

$\implies \sf x =\: \dfrac{\cancel{140}}{\cancel{2}}$

$\implies \sf x =\: \dfrac{70}{1}$

$\implies \sf\bold{\red{x =\: 70}}$

$\therefore$ The LCM of two numbers is 70.

$\rule{150}{2}$

VERIFICATION :-

$\dashrightarrow \rm\bold{HCF \times LCM =\: Product\: of\: two\: numbers}$

$\leadsto \rm 2 \times x =\: 140$

By putting x = 70 we get,

$\leadsto \rm 2 \times 70 =\: 140$

$\leadsto \rm\bold{\purple{140 =\: 140}}$

Hence, Verified.

Answer 2

Question :

• Find the LCM of two numbers if their is140 and the HCF is 2

Given :

• Product = 140
• HCF = 2

To Find :

• Find the LCM of 2 numbers.

Let's Start :

Let the LCM be = x

As we know :

${\boxed {\boxed {\underline{ \pink{ \sf \: HCF × LCM = Product \: of \: 2 \: numbers}}}}}$

Let's Do !

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \purple{: \implies} \sf 2 × x = 140 \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \purple{: \implies }x = \cancel\dfrac{140}{2} \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \purple{: \implies} \sf \: x = 70$

Let's Verify :

${\boxed {\boxed {\underline{ \pink{ \sf \: HCF × LCM = Product \: of \: 2 \: numbers}}}}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \purple{: \implies} \sf2 \times 70 = 140 \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \purple{: \implies} \sf140 = 140$

Hence it is verified :)