find the LCM of two numbers whose product is 1584 and HCF is 6 find the number
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2
Answer:
Let factorize the LCM
1584 = 2x2x2x2x3x3x11
Since 11 is a factor, in the LCM, one of the numbers must be a multiple of 11, and multiples of 2. Say the number is 176. Its factors will be 2x2x2x2x11
One number must be a multiple of 16. Let us try 320–176 = 144. Its factors are 2x2x2x2x3x3.
The LCM of 176 and 144 = 2x2x2x2x3x3x11.
So the numbers are 144 and 176.
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LCM×HCF=one number× another number
LCM× 6=1584
LCM=1584/6
LCM=264
the two numbers are 24 and 66
1584=2×2×2×2×3×3×11
6=2×3
LCM=2×3×2×2=24
HCF=2×3 ×11=66
if this answer helps u mark as brainliest
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