Question

Find the LCM of (x + 3) (6x2 + 5x + 4) and (2x2 + 7x + 3) (x + 3)

Answer 1

Answer:

(x +3)(6x²+5x-4) = (x+3)(6x²-3x+8x-4)

= (x+3)[3x(2x-1)+4(2x-1)]

= (x+3)(3x+4)(2x-1)

(2x²+7x+3)(x+3) = (2x²+6x+x+3)(x+3)

= [2x(x+3) + 1(x+3)] (x+3)

ans: = (2x + 1)(x+3)²

Hope it helps

Answer 2

Answer:

(4x^2-1)(3x+4)(x+3)^2

Step-by-step explanation:

i) (x+3)(6x^2+5x+4)

= (x+3)[3x(2x-1)+4(2x-1)]

= (x+3)(3x+4)(2x-1)

ii) (2x^2+7x+3)(x+3)

= [2x(x+3)+1(x+3)](x+3)

= [2x+1][x+3](x+3).

Putting both equations together we get,

(x+3)(3x+4)(2x-1)(2x+1)(x+3)

(x+3)^2(3x+4)(4x^2-1).

(x+3) from equation 2 has been taken as common...and (2x-1)(2x+1) has been solved using the equation (a+b)(a-b) which results in (a^2-b^2).