Question

find the LCM of x2 - 4 and x4 - 16

Answer 1

HI.................

@MADBRO

Answer 2

The LCM of   $x^{2} -4$   and   $x^{2} -16$   is   $(x^{2} -4)(x^{2} +4)$

Given :

The equations $x^{2} -4$   and   $x^{2} -16$

To find :

The LCM of   $x^{2} -4$   and  $x^{2} -16$

Solution :

The equation $x^{2} -4$ can be simplified as

                                 $x^{2} -4$ = $x^{2} -2^{2}$

                                           = (x-2) (x+2)

The equation $x^{2} -16$ can be simplified as

                                    $x^{2} -16$ = $(x^{2} )^{2}- 4^{2}$

                                                 =  ($x^{2} -4$)($x^{2} +4$)

                                                 = (x-2) (x+2)($x^{2} +4$)

The LCM of (x-2) (x+2)($x^{2} +4$) is

LCM = (x-2) (x+2)($x^{2} +4$)

        = ($x^{2} -4$)($x^{2} +4$)

#SPJ3