find the LCM of x2-xy-2y2, 2x2-5xy+2y2, 2x2+xy-y2
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Answer:
(2x-y)(x-2y)(x+y)
Step-by-step explanation:
The factrors of x2-xy-2y2 are
x2-xy-2y2
=x2-2xy+xy-2y2
=x(x-2y)+y(x-2y)
=(x-2y)(x+y)
The factors of 2x2-5xy+2y2
=2x2-4xy-xy+2y2
=2x(x-2y)-y(x-2y)
=(x-2y)(2x-y)
The factors or 2x2+xy-y2
=2x2+2xy-xy-y2
=2x(x+y)-y(x+y)
=(x+y)(2x-y)
Therefore the L.C.M is (2x-y)(x-2y)(x+y)
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